-4w^2+7w+2=0

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Solution for -4w^2+7w+2=0 equation: 



-4w^2+7w+2=0

a = -4; b = 7; c = +2;
Δ = b2-4ac
Δ = 72-4·(-4)·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-9}{2*-4}=\frac{-16}{-8}
=+2
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+9}{2*-4}=\frac{2}{-8}
=-1/4
$

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